ProofModerate1 mark
2(iii)
In ΔABC, ∠ABC = 90°, AB = 20 cm, AC = 25 cm, DE is perpendicular to AC such that ∠DEA = 90° and DE = 3 cm as shown in the given figure.
Prove that ΔABC ~ ΔAED.
Topic: Similarity / scale factor
Previous-year question practice database
Answer
Exam answer
ΔABC ∼ ΔAED
Explanation
∠ABC=∠AED=90° and ∠BAC=∠EAD (common angle), so AA similarity.
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