Short answerEasy1 mark
5(b)
A half metre rod is pivoted at the centre with two weights of 20 gf and 12 gf suspended at a perpendicular distance of 6 cm and 10 cm from the pivot respectively as shown below.
The direction of 20 gf force is reversed. What is the magnitude of the resultant moment of the forces on the rod?
Topic: Force, moments and circular motion
Previous-year question practice database
Answer
Exam answer
240 gf cm.
Explanation
After reversing the 20 gf force, both moments act in the same direction: 120 + 120 = 240 gf cm.
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