NumericalModerate2 marks
7(ii)
In the given graph, P and Q are points such that PQ cuts off intercepts of 5 units and 3 units along the x-axis and y-axis respectively. Line RS is perpendicular to PQ and passes through the origin. Find the:
equation of line RS
Topic: Slope / equation of line
Previous-year question practice database
Answer
Exam answer
P(5,0), Q(0,−3).
Slope of PQ = (−3−0)/(0−5) = 3/5.
Since RS ⟂ PQ: mRS × 3/5 = −1 mRS = −5/3.
RS passes through the origin: y = −5x/3
5x + 3y = 0.
Answer: 5x + 3y = 0.
Explanation
For perpendicular non-vertical lines, the product of slopes is −1. Then use the point-slope equation through the origin.
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