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ICSE Question Bank
2024Q6(ii)(b)Arithmetic Progression
NumericalModerate1.5 marks
6(ii)

The nth term of an Arithmetic Progression (A.P.) is given by the relation Tn = 6(7 - n). Find ∶

sum of its first 25 terms

Topic: Arithmetic progression

Previous-year question practice database

Answer

Exam answer

S₂₅ = −900.

Explanation

S₂₅=25/2[2(36)+24(−6)] = 25/2(−72)=−900.

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