NumericalEasy1 mark
3(b)
In the given figure below, AD is a diameter. O is the centre of the circle. AD is parallel to BC and ∠CBD = 32°. Find:
∠AOB
Topic: Circle theorems
Previous-year question practice database
Answer
Exam answer
AOB=64°
Explanation
ADisparallel toBC, i.e., AOisparallel toBC andOBis transversal. AOB= OBC .... Alternateangles BC= OBD+ DBC OBC=32°+32° OBC=64° AOB=64° ⇒ √ √ ⇒ √ √ √ ⇒ √ ⇒ √ ⇒ √ O