Write the value of n after execution: char ch = 'd'; int n = ch + 5;

n = 105

When a char takes part in arithmetic, Java promotes it to its ASCII value. 'd' is 100 (working from the anchor 'a' = 97: b = 98, c = 99, d = 100). So n = 100 + 5 = 105. Because n is declared int, the number itself is stored and printed. Had it been declared char, the value 105 would have been shown as the character 'i' instead — the same arithmetic, a different display. Fix the anchors: A = 65, a = 97, 0 = 48.