Short answerModerate2 marks
What are the two ways of invoking functions?
Topic: Invoking functions
Previous-year question practice database
Answer
Exam answer
Call by value and call by reference.
Explanation
Name both and say what distinguishes them, since a bare list rarely earns full marks. Call by value — a copy of the value is passed, so changes made inside the method do not affect the original. This happens with primitives. Call by reference — the address of the object is passed, so changes made inside DO affect the original. This happens with objects and arrays. The practical consequence: a method cannot swap two ints passed to it, but can change the contents of an array passed to it.
More from User-Defined Methods
In the following method prototype to accept a character, an integer and return YES or NO, fill in the blank to complete the method prototype.
public __________ someMethod(char ch, int n)2026In a calculator which Java feature allows multiple methods named calculate() for the different operations?2026The following program segment calculates and displays the factorial of a number. [Example: Factorial of 5 is 1 x 2 x 3 x 4 x 5 = 120]
int p, n = 5, f = 0;
for(p = n; p > 0; p--)
f *= p;
System.out.println(f);
Name the type of error if any; correct the statement to get the desired output.2026Define a class to overload the method format as follows:
void format() - To print the following pattern using Nested for loops only:
1 2 3 4 5
2 3 4 5
3 4 5
4 5
5
int format(String s) - To calculate and return the sum of ASCII codes of each character of the String.
Example: CAB
Output: 67 + 65 + 66 = 198
void format(int n) - To calculate and display the sum of natural numbers up to n given by the formula n(n + 1) / 2.2026Which of the following pairs of methods will cause a compile-time error due to incorrect method overloading?2025Consider the following program segment in which the statements are jumbled. Choose the correct order of statements to calculate and return the factorial of 4.
1. for(k = 1; k <= 4; k++)
2. return fa;
3. long fa = 1, k;
4. fa *= k;2025