NumericalEasy1 mark
10(iii)
The given graph represents the monthly salaries (in ₹) of workers of a factory. Using graph answer the following:
the median class.
Topic: Mean / median / mode / quartiles
Previous-year question practice database
Answer
Exam answer
| Monthly salary (₹) | Cumulative frequency |
|---|---|
| 0–2,000 | 10 |
| 2,000–4,000 | 20 |
| 4,000–6,000 | 35 |
| 6,000–8,000 | 55 |
| 8,000–10,000 | 70 |
| 10,000–12,000 | 75 |
N = 75. Median position = (N+1)/2 = 38th worker. The 38th worker lies in the ₹6,000–₹8,000 class.
Answer: Median class = ₹6,000–₹8,000.
Explanation
Use the cumulative-frequency values directly and locate the requested position/range.
More from Measure of Central Tendency (Mean, Median, Quartiles and Mode)
Rakhi’s mobile number has the following integers :
1, 6, 9, 8, 9, 1, 7, 8, 9
The mode of the above given data is :2026Find the mean of the following frequency distribution using step-deviation method.
Take assumed mean = 282026Assertion (A): The mean of first 9 natural numbers is 4.5.
Statement 2: Mean = Sum of all observations / Total number of observations2025mean, to the nearest whole number2025median2025the total number of workers.2025