ConstructionModerate1 mark
10(c)
Use ruler and compass for this question. Construct a circle of radius 4.5 cm. Draw a chord AB = 6 cm.
Join AD and find the locus of points which are equidistant from AD and AB. Mark the point where it meets the circle as C.
Topic: Loci
Previous-year question practice database
Answer
Solution diagram
Exam answer
The locus of points equidistant from the lines AD and AB is an angle bisector of ∠DAB.
Construction: Construct the internal angle bisector of ∠DAB and extend it to meet the circle at C.
Answer:
C is the point where the internal angle bisector of ∠DAB meets the circle.
Explanation
A point is equidistant from two intersecting lines if it lies on an angle bisector of the angle between them. The internal angle bisector is used to locate C inside the required region.
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